A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.

Now given an M x N matrix, return True if and only if the matrix is Toeplitz.

Input: matrix = [[1,2,3,4],[5,1,2,3],[9,5,1,2]]Output: TrueExplanation:123451239512In the above grid, the diagonals are "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]", and in each diagonal all elements are the same, so the answer is True.Input: matrix = [[1,2],[2,2]]Output: FalseExplanation:The diagonal "[1, 2]" has different elements.Note:matrix will be a 2D array of integers.matrix will have a number of rows and columns in range [1, 20].matrix[i][j] will be integers in range [0, 99].

思路

这纯粹是一道找规律的题目，每一行的前n-1个数和下一行的后n-1个数相同

class Solution(object):    def isToeplitzMatrix(self, matrix):        """        :type matrix: List[List[int]]        :rtype: bool        """        flag = False        for key,value in enumerate(matrix):            if key + 1< len(matrix):                if value[:-1] == matrix[key+1][1:]:                    continue                else:                    flag = False                    break            else:                flag = True        return flag